LastIndexOf method

Searches for a string within a string in reverse order and returns the found position counting from the beginning (unless the start position is indicated).

Syntax

str₁.LastIndexOf(str₂ [ , start-position ] )

Where:

str₁
    String on which the search will be done. It may be an attribute or variable based on the Character/VarChar/LongVarChar data type.  

str₂
    Search string. It may be a fixed value, an attribute or variable based on the Character/VarChar/LongVarChar data type.

start-position
     Optional. It indicates the search start position. It must be a positive number.

Type Returned:
Numeric

Scope

Data Types: Character, VarChar, LongVarChar
Generators: .NET, .NET Framework, Java, Ruby (up to GeneXus X Evolution 3), Visual FoxPro (up to GeneXus X Evolution 3)

Description

This method searches for a string within a string in reverse order. If the last parameter is omitted, it searches from the first position of the str₁. If the search is not successful, it returns 0.

 Notes:

• The start-position parameter must be a positive number. It indicates the initial position of the search within the str₁.  If it is 0, both functions return to 0.
• The comparison between characters is case sensitive; i.e.:  'a' is different from 'A'.
• If str₁ is empty or the length is shorter than str₂, both functions return 0, since the search cannot be carried out.
• If str₂ is empty, it returns start-position if it was initialized. Otherwise, it returns 1.

Samples

&str1 = "Of LastIndexOf test"
&Nbr=&str1.LastIndexOf("e")      //&Nbr= 17
&Nbr=&str1.LastIndexOf("In")     //&Nbr= 8
&Nbr=&str1.LastIndexOf("Last")   //&Nbr= 4
&Nbr=&str1.LastIndexOf("O")      //&Nbr= 13
&Nbr=&str1.LastIndexOf("Of")     //&Nbr= 13
&Nbr=&str1.LastIndexOf("Of",1)   //&Nbr= 1

See Also

IndexOf method
StrSearchRev function
StrReplace function